Thank you for visiting A 25 0 mL sample of a saturated tex Ca OH 2 tex solution is titrated with 0 026 M HCl The equivalence point is. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Sure, let's find the concentration of the saturated [tex]\( Ca(OH)_2 \)[/tex] solution step-by-step.
1. Understand the Reaction:
The balanced chemical reaction for titrating [tex]\( Ca(OH)_2 \)[/tex] with [tex]\( HCl \)[/tex] is:
[tex]\[ Ca(OH)_2 + 2HCl \rightarrow CaCl_2 + 2H_2O \][/tex]
This tells us that 1 mole of [tex]\( Ca(OH)_2 \)[/tex] reacts with 2 moles of [tex]\( HCl \)[/tex].
2. Determine Moles of [tex]\( HCl \)[/tex] Used:
You have 35.9 mL of 0.026 M [tex]\( HCl \)[/tex]. First, convert the volume from mL to L by dividing by 1000:
[tex]\[ 35.9 \, \text{mL} = 0.0359 \, \text{L} \][/tex]
Calculate the moles of [tex]\( HCl \)[/tex] using the formula:
[tex]\[ \text{moles of } HCl = \text{Molarity} \times \text{Volume (L)} \][/tex]
[tex]\[ \text{moles of } HCl = 0.026 \, \text{M} \times 0.0359 \, \text{L} = 0.0009334 \, \text{moles} \][/tex]
3. Relate Moles of [tex]\( HCl \)[/tex] to Moles of [tex]\( Ca(OH)_2 \)[/tex]:
According to the balanced equation, 2 moles of [tex]\( HCl \)[/tex] react with 1 mole of [tex]\( Ca(OH)_2 \)[/tex]. Therefore, divide the moles of [tex]\( HCl \)[/tex] by 2 to find moles of [tex]\( Ca(OH)_2 \)[/tex]:
[tex]\[ \text{moles of } Ca(OH)_2 = \frac{0.0009334}{2} = 0.0004667 \, \text{moles} \][/tex]
4. Calculate Concentration of [tex]\( Ca(OH)_2 \)[/tex]:
The volume of the [tex]\( Ca(OH)_2 \)[/tex] solution is 25.0 mL. Convert this to liters:
[tex]\[ 25.0 \, \text{mL} = 0.0250 \, \text{L} \][/tex]
Find the concentration using the formula:
[tex]\[ \text{Concentration (M)} = \frac{\text{moles}}{\text{Volume (L)}} \][/tex]
[tex]\[ \text{Concentration of } Ca(OH)_2 = \frac{0.0004667}{0.0250} = 0.018668 \, \text{M} \][/tex]
So, the concentration of the saturated [tex]\( Ca(OH)_2 \)[/tex] solution is approximately 0.01867 M.
1. Understand the Reaction:
The balanced chemical reaction for titrating [tex]\( Ca(OH)_2 \)[/tex] with [tex]\( HCl \)[/tex] is:
[tex]\[ Ca(OH)_2 + 2HCl \rightarrow CaCl_2 + 2H_2O \][/tex]
This tells us that 1 mole of [tex]\( Ca(OH)_2 \)[/tex] reacts with 2 moles of [tex]\( HCl \)[/tex].
2. Determine Moles of [tex]\( HCl \)[/tex] Used:
You have 35.9 mL of 0.026 M [tex]\( HCl \)[/tex]. First, convert the volume from mL to L by dividing by 1000:
[tex]\[ 35.9 \, \text{mL} = 0.0359 \, \text{L} \][/tex]
Calculate the moles of [tex]\( HCl \)[/tex] using the formula:
[tex]\[ \text{moles of } HCl = \text{Molarity} \times \text{Volume (L)} \][/tex]
[tex]\[ \text{moles of } HCl = 0.026 \, \text{M} \times 0.0359 \, \text{L} = 0.0009334 \, \text{moles} \][/tex]
3. Relate Moles of [tex]\( HCl \)[/tex] to Moles of [tex]\( Ca(OH)_2 \)[/tex]:
According to the balanced equation, 2 moles of [tex]\( HCl \)[/tex] react with 1 mole of [tex]\( Ca(OH)_2 \)[/tex]. Therefore, divide the moles of [tex]\( HCl \)[/tex] by 2 to find moles of [tex]\( Ca(OH)_2 \)[/tex]:
[tex]\[ \text{moles of } Ca(OH)_2 = \frac{0.0009334}{2} = 0.0004667 \, \text{moles} \][/tex]
4. Calculate Concentration of [tex]\( Ca(OH)_2 \)[/tex]:
The volume of the [tex]\( Ca(OH)_2 \)[/tex] solution is 25.0 mL. Convert this to liters:
[tex]\[ 25.0 \, \text{mL} = 0.0250 \, \text{L} \][/tex]
Find the concentration using the formula:
[tex]\[ \text{Concentration (M)} = \frac{\text{moles}}{\text{Volume (L)}} \][/tex]
[tex]\[ \text{Concentration of } Ca(OH)_2 = \frac{0.0004667}{0.0250} = 0.018668 \, \text{M} \][/tex]
So, the concentration of the saturated [tex]\( Ca(OH)_2 \)[/tex] solution is approximately 0.01867 M.
Thank you for reading the article A 25 0 mL sample of a saturated tex Ca OH 2 tex solution is titrated with 0 026 M HCl The equivalence point is. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
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