High School

Thank you for visiting If a gas effuses 1 73 times faster than Kr what is its molar mass a 16 0 g mol b 28 0 g mol. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

If a gas effuses 1.73 times faster than Kr, what is its molar mass?

a) 16.0 g/mol
b) 28.0 g/mol
c) 36.6 g/mol
d) 55.4 g/mol
e) 126.9 g/mol

Answer :

Final answer:

To determine the molar mass of the unknown gas that effuses 1.73 times faster than Kr, we can use Graham's law of effusion. The molar mass of the unknown gas is approximately 36.6 g/mol.

Explanation:

To determine the molar mass of the unknown gas, we can use Graham's law of effusion. Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Given that the unknown gas effuses 1.73 times faster than Kr, we can set up the following equation: (Rate of unknown gas) / (Rate of Kr) = sqrt(Molar mass of Kr) / sqrt(Molar mass of unknown gas)

Plugging in the values, we get:

  • (1.73) / (1) = sqrt(83.8 g/mol) / sqrt(Molar mass of unknown gas)
  • Solving for the molar mass of the unknown gas, we find:
  • Molar mass of unknown gas = (sqrt(83.8 g/mol))^2 / (1.73)^2
  • Molar mass of unknown gas = 36.6 g/mol (approximately)
  • Therefore, the correct answer is option c) 36.6 g/mol.

Thank you for reading the article If a gas effuses 1 73 times faster than Kr what is its molar mass a 16 0 g mol b 28 0 g mol. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany

Other Questions