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Answer :
To find how many grams of [tex]\( Fe_2O_3 \)[/tex] are there in 0.500 moles of [tex]\( Fe_2O_3 \)[/tex], follow these steps:
1. Calculate the molar mass of [tex]\( Fe_2O_3 \)[/tex]:
- First, find the molar mass of iron (Fe). The atomic mass of iron is approximately 55.845 g/mol.
- For oxygen (O), the atomic mass is approximately 16.00 g/mol.
The chemical formula for [tex]\( Fe_2O_3 \)[/tex] consists of 2 iron (Fe) atoms and 3 oxygen (O) atoms.
- Calculate the total molar mass:
[tex]\[
\text{Molar mass of } Fe_2O_3 = (2 \times 55.845) + (3 \times 16.00)
\][/tex]
[tex]\[
= 111.69 + 48.00
\][/tex]
[tex]\[
= 159.69 \, \text{g/mol}
\][/tex]
2. Calculate the mass of 0.500 moles of [tex]\( Fe_2O_3 \)[/tex]:
- Use the formula:
[tex]\[
\text{Mass} = \text{moles} \times \text{molar mass}
\][/tex]
- Substitute the given values:
[tex]\[
\text{Mass of } Fe_2O_3 = 0.500 \, \text{moles} \times 159.69 \, \text{g/mol}
\][/tex]
[tex]\[
= 79.845 \, \text{g}
\][/tex]
Based on the options given, the closest match is option D) 79.9 g.
Therefore, there are approximately 79.9 grams of [tex]\( Fe_2O_3 \)[/tex] in 0.500 mole of [tex]\( Fe_2O_3 \)[/tex].
1. Calculate the molar mass of [tex]\( Fe_2O_3 \)[/tex]:
- First, find the molar mass of iron (Fe). The atomic mass of iron is approximately 55.845 g/mol.
- For oxygen (O), the atomic mass is approximately 16.00 g/mol.
The chemical formula for [tex]\( Fe_2O_3 \)[/tex] consists of 2 iron (Fe) atoms and 3 oxygen (O) atoms.
- Calculate the total molar mass:
[tex]\[
\text{Molar mass of } Fe_2O_3 = (2 \times 55.845) + (3 \times 16.00)
\][/tex]
[tex]\[
= 111.69 + 48.00
\][/tex]
[tex]\[
= 159.69 \, \text{g/mol}
\][/tex]
2. Calculate the mass of 0.500 moles of [tex]\( Fe_2O_3 \)[/tex]:
- Use the formula:
[tex]\[
\text{Mass} = \text{moles} \times \text{molar mass}
\][/tex]
- Substitute the given values:
[tex]\[
\text{Mass of } Fe_2O_3 = 0.500 \, \text{moles} \times 159.69 \, \text{g/mol}
\][/tex]
[tex]\[
= 79.845 \, \text{g}
\][/tex]
Based on the options given, the closest match is option D) 79.9 g.
Therefore, there are approximately 79.9 grams of [tex]\( Fe_2O_3 \)[/tex] in 0.500 mole of [tex]\( Fe_2O_3 \)[/tex].
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