Thank you for visiting If your front lawn is 15 0 feet wide and 20 0 feet long and each square foot of lawn accumulates 1450 new snowflakes every. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
First determine how many square feet there are in the front lawn.
(15.0 ft) x (20.0 ft) = 300. ft^2
Now find how many snow flakes land in the entire lawn.
(300. ft^2) x (1450 snow flakes/min/ft^2) = 435,000 snow flakes/min
Now find the total mass of snow landing on the lawn per hour.
(435,000 snow flakes/min) x (1.70 mg/snow flake) x (1 kg/1,000,000 mg) x (60 min/1hour) = 44.4 kg of snow per hour.
(15.0 ft) x (20.0 ft) = 300. ft^2
Now find how many snow flakes land in the entire lawn.
(300. ft^2) x (1450 snow flakes/min/ft^2) = 435,000 snow flakes/min
Now find the total mass of snow landing on the lawn per hour.
(435,000 snow flakes/min) x (1.70 mg/snow flake) x (1 kg/1,000,000 mg) x (60 min/1hour) = 44.4 kg of snow per hour.
Thank you for reading the article If your front lawn is 15 0 feet wide and 20 0 feet long and each square foot of lawn accumulates 1450 new snowflakes every. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
- You are operating a recreational vessel less than 39 4 feet long on federally controlled waters Which of the following is a legal sound device
- Which step should a food worker complete to prevent cross contact when preparing and serving an allergen free meal A Clean and sanitize all surfaces
- For one month Siera calculated her hometown s average high temperature in degrees Fahrenheit She wants to convert that temperature from degrees Fahrenheit to degrees
Rewritten by : Jeany
