Thank you for visiting A random sample of IQ tests is normally distributed with a mean of 99 8 and a standard deviation of 15 3 Jan has an. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
To find the z-score for Jan's IQ of 89, we can use the formula: z = (x - mean) / standard deviation. Plugging in the values, we get: z = (89 - 99.8) / 15.3 = -0.706. The z-score represents the number of standard deviations Jan's IQ score is from the mean.
To find the z-score for Jan's IQ of 89, we can use the formula: z = (x - mean) / standard deviation. Plugging in the values, we get: z = (89 - 99.8) / 15.3 = -0.706. The z-score represents the number of standard deviations Jan's IQ score is from the mean.
For the second part of the question, since the z-score for Jan's IQ of 89 is negative, it means Jan's IQ is below the mean. We can use a z-table or a z-score calculator to find the probability associated with the z-score. In this case, the probability is approximately 0.2419 or 24.19%.
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The complete question is,
13. A random sample of IQ tests is normally distributed with a mean of 99.8 and a standard deviation of 15.3. Jan has an IQ of 89. Use this information to answer the following Z-score questions. a) Calculate the Z-score for Jan's' IQ. b) Write a sentence to explain the Z-score in context. c) Is Jan's' IQ unusually low compared to other people in the data set? Explain your answer.
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