Thank you for visiting A rifle is aimed horizontally at a target 58 m away The bullet hits the target 2 1 cm below the aim point What was. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
The time of flight of a bullet shot horizontally can be calculated based on the vertical displacement of the bullet and the acceleration due to gravity. Our calculation, using the simplified equation of motion, shows that the bullet was in flight for approximately 0.07 seconds before hitting the target 2.1 cm below the aim point.
Explanation:
To calculate the bullet's flight time, we need to utilize the physics principle called free-fall motion or projectile motion. First, we are given that the bullet falls 2.1 cm or 0.021 m below the aim point — this is the vertical displacement. Since the bullet is shot horizontally, the initial vertical velocity is 0 m/s. We also know the acceleration due to gravity is -9.81 m/s² (negative because the direction of motion is downwards).
From the equation of motion, Δy = Vyi*t - 0.5*g*t², because the bullet was shot horizontally, the initial vertical velocity Vyi is 0, and thus the equation is simplified to Δy = -0.5*g*t². Solving for time 't' gives us √(-2Δy/g), providing the exact time of flight.
Substituting our given values into our modified equation, we yield that: t = √( -2*(-0.021m) / -9.81m/s² ) = 0.07 seconds. Hence, the bullet was in flight for around 0.07 seconds before reaching its target.
Learn more about Projectile Motion here:
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