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A rifle is aimed horizontally at a target 50 m away. The bullet hits the target 2.2 cm below the aim point.

What was the bullet's flight time, and what was the speed it left the barrel?

Answer :

Final answer:

The question relates to projectile motion in physics. Given a horizontal distance and a vertical deviation, we can calculate the time of flight and the bullet's initial speed. The bullet was in flight for approximately 0.067 seconds and left the barrel at a speed of roughly 746.2687 m/s.

Explanation:

The subject of your question pertains to projectile motion in physics. In an ideal case, where we ignore air resistance, a bullet fired horizontally experiences only constant downward acceleration from gravity, which doesn't affect its horizontal speed. We can find the time of flight by using the equation of motion d = 0.5gt², where d is the vertical deviation, g is the acceleration due to gravity (approximated as 9.8m/s²), and t is the time. Substituting the given d value of 0.022m (2.2 cm converted to meters), we can solve for t, which comes out as ~0.067 seconds. As the bullet is moving horizontally, we can find the speed with which it left the barrel by using the simple formula - speed = distance/time, which gives us approximately 746.2687 m/s.

Learn more about Projectile Motion here:

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