A sealed plastic syringe has a pressure of 97.8 kPa at a temperature of 402 K. If the syringe's temperature changes to 251 K, what will be the new pressure?

Question

15-12-2023
Physics

High School

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A sealed plastic syringe has a pressure of 97.8 kPa at a temperature of 402 K. If the syringe's temperature changes to 251 K, what will be the new pressure?

Answer :

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CarloAire CarloAire · Answer 1 · 2023-11-04T02:18:28-04:00

Final answer:

To find the new pressure when the temperature is changed from 402 K to 251 K, we can use Gay-Lussac's Law. The new pressure will be approximately 61.3 kPa.

Explanation:

When a sealed plastic syringe undergoes a change in temperature, its pressure also changes. In this case, the original pressure is 97.8 kPa at a temperature of 402 K.

To find the new pressure when the temperature is 251 K, we can use Gay-Lussac's Law.

Gay-Lussac's Law states that the pressure of a gas is directly proportional to its temperature, as long as the volume and amount of gas are constant.

We can use the formula Pâ‚/Tâ‚ = Pâ‚‚/Tâ‚‚, where Pâ‚ and Tâ‚ are the initial pressure and temperature, and Pâ‚‚ and Tâ‚‚ are the final pressure and temperature.

Plugging in the given values, we have 97.8 kPa / 402 K = Pâ‚‚ / 251 K.

Solving for Pâ‚‚, we get Pâ‚‚ = (251 K * 97.8 kPa) / 402 K ≈ 61.3 kPa.

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