Thank you for visiting A solenoid with 1 107 turns has a radius of 82 4 mm and is 39 4 cm long If this solenoid carries a current. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
The magnitude of the magnetic field near the center of the solenoid is approximately 0.670 T.
Explanation:
To determine the magnitude of the magnetic field near the center of a solenoid, you can use the formula:
B = μâ‚€ * N * I / L
Where:
- B is the magnetic field strength
- μâ‚€ is the permeability of free space (4π × 10-7 T m/A)
- N is the number of turns in the solenoid
- I is the current through the solenoid
- L is the length of the solenoid
Plugging in the given values:
- μâ‚€ = 4π × 10-7 T m/A
- N = 1,107 turns
- I = 67.2 A
- L = 0.394 m
Calculating:
- B = (4π × 10-7) * (1,107) * (67.2) / (0.394)
- B ≈ 0.670 T
Therefore, the magnitude of the magnetic field near the center of the solenoid is approximately 0.670 T.
Learn more about Magnetic Field Inside a Solenoid here:
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