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Thank you for visiting Calculate Delta S circ for the following reaction text SnCl 4 l rightarrow text SnCl 2 g A 107 J K B 625 J K. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

Calculate \(\Delta S^\circ\) for the following reaction:

\[ \text{SnCl}_4(l) \rightarrow \text{SnCl}_2(g) \]

A) 107 J/K
B) -625 J/K
C) 625 J/K
D) -107 J/K

Answer :

The standard entropy change[tex](\( \Delta S^\circ \))[/tex] for SnClâ‚„(l) → SnClâ‚„(g) is approximately +18 J/K mol.

To calculate the standard entropy change[tex](\( \Delta S^\circ \)) for the reaction:\[ \text{SnCl}_4 (l) \rightarrow \text{SnCl}_4 (g) \]we can use the standard entropy values (\( S^\circ \)) for the substances involved. The standard entropy change is given by the formula:[/tex]

[tex]\[ \Delta S^\circ = \sum nS^\circ_{\text{products}} - \sum mS^\circ_{\text{reactants}} \]where \( n \) and \( m \) are the coefficients of the products and reactants in the balanced chemical equation, and \( S^\circ \) is the standard entropy.For this reaction, the equation is:\[ \text{SnCl}_4 (l) \rightarrow \text{SnCl}_4 (g) \][/tex]

The products and reactants are:

[tex]\[ \text{Products:} \, \text{SnCl}_4 (g) \]\[ \text{Reactants:} \, \text{SnCl}_4 (l) \]We need to find the standard entropy values for \( \text{SnCl}_4 (l) \) and \( \text{SnCl}_4 (g) \). According to standard thermodynamic data, the standard entropy values are approximately:\[ S^\circ_{\text{SnCl}_4 (l)} = 308 \, \text{J/K mol} \]\[ S^\circ_{\text{SnCl}_4 (g)} = 326 \, \text{J/K mol} \]Now, substitute these values into the formula for \( \Delta S^\circ \):[/tex]

[tex]\[ \Delta S^\circ = S^\circ_{\text{SnCl}_4 (g)} - S^\circ_{\text{SnCl}_4 (l)} \]\[ \Delta S^\circ = 326 \, \text{J/K mol} - 308 \, \text{J/K mol} \]\[ \Delta S^\circ = 18 \, \text{J/K mol} \]So, the standard entropy change for the given reaction is \( \Delta S^\circ = +18 \, \text{J/K mol} \).[/tex]

Comparing this to the answer choices provided:

(A) 107 J/K

(B) -625 J/K

(C) 625 J/K

(D) -107 J/K

The closest answer is (A) 107 J/K. However, please double-check the given choices, as the calculated value is not exactly matching any of them.

Thank you for reading the article Calculate Delta S circ for the following reaction text SnCl 4 l rightarrow text SnCl 2 g A 107 J K B 625 J K. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany