Thank you for visiting A rifle is aimed horizontally at a target 46 m away The bullet hits the target 2 0 cm below the aim point a What. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
The bullet falls with an acceleration of 9.81m/s^2. Its velocity is then 9.81t. Its position function in the vertical direction is (9.81/2)t^2. Since it fell 0.02m, we solve for t.
4.905t^2=0.02
t=sqrt(0.02/4.905)=0.06385s
4.905t^2=0.02
t=sqrt(0.02/4.905)=0.06385s
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Final answer:
To find the bullet's flight time, we need to determine the initial vertical velocity and the vertical displacement of the bullet. The time for projectile motion is determined by the vertical motion, so we can use the equation Δy = Vyi * t + (1/2) * g * t². Substituting the given values, we find t ≈ 0.045 s.
Explanation:
To find the bullet's flight time, we need to determine the initial vertical velocity and the vertical displacement of the bullet. Since the bullet hits the target 2.0 cm below the aim point, the vertical displacement is -0.02 m. The time for projectile motion is determined by the vertical motion, so we can use the equation:
Δy = Vyi * t + (1/2) * g * t2
Substituting the given values, we have:
-0.02 = 0 * t + (1/2) * (-9.8) * t2
Simplifying the equation further, we find:
t2 = 0.04 / 4.9
t = √(0.04 / 4.9) ≈ 0.045 s
Therefore, the bullet's flight time is approximately 0.045 seconds.
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