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To prove that AEB and CED intersect at E, we can use the properties of triangles and angles.
To prove that AEB and CED intersect at E, we can use the properties of triangles and angles. We need to show that triangle AEB and triangle CED share one common vertex, which is E, and also share at least one side. This can be done by showing that angle AEB is equal to angle CED and that line segment AE is equal to line segment CE.
Now, using the properties of triangles and angles, we can prove that the two angles are equal by showing that they are both congruent right angles or that they are vertical angles and therefore equal.
Next, we can prove that line segment AE and line segment CE are equal in length by using the properties of congruent triangles or by applying the segment addition postulate to show that line segment AE + line segment EB is equal to line segment CE + line segment ED.
Therefore, since we have proven that angle AEB is equal to angle CED and line segment AE is equal to line segment CE, we can conclude that AEB and CED intersect at E.
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