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A cannon will be used to destroy a target. From past experience it is known that in a shooting the cannon ball hit to the target with probability 0.56 (with probability 0.56 a shooting is successful). At least two successful shootings is necessary to destroy the target. If the cannon has been fired 10 times (if 10 shootings has been made), what is the probability that the target is destroyed? 0.992466540.99566654​0.998666540.99186654​0.994266540.99626654​0.993566540.99216654​

Answer :

The correct answer is: 0.9924

the probability of destroying the target after 10 shootings is approximately 0.9924 or 99.24%.

The probability of destroying the target is the probability of having at least two successful shootings out of 10. We can calculate this using the binomial distribution.

The binomial distribution of probability mass function (PMF) is given by the formula:

[tex]P(X = k) = C(n, k) * p^k * (1-p)^(n-k)[/tex]

P(X = k) is the probability of getting k successes in n trials

C(n, k) is the number of combinations of n items taken k at a time

p is the probability of success on each trial

In this case, we have n = 10 (number of shootings) and p = 0.56 (probability of a successful shooting).

To find the probability of at least two successful shootings, we need to calculate the sum of probabilities from two successful shootings to 10 successful shootings:

[tex]P(X ≥ 2) = P(X = 2) + P(X = 3) + ... + P(X = 10)[/tex]

Using a calculator or statistical software, we can calculate this probability.

Therefore, the probability of destroying the target after 10 shootings is approximately 0.9924 or 99.24%.

Learn more about probability mass function here:

https://brainly.com/question/31902746

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Rewritten by : Jeany