Thank you for visiting How many grams of iron III oxide are there in 0 500 mol of this substance A 160 g B 63 8 g C 35. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
To find out how many grams of iron(III) oxide (Fe₂O₃) are in 0.500 moles of this substance, we need to use the molar mass of Fe₂O₃.
First, let's calculate the molar mass of Fe₂O₃. Iron (Fe) has an atomic mass of approximately 55.8 g/mol, and oxygen (O) has an atomic mass of approximately 16.0 g/mol.
The chemical formula of iron(III) oxide is Fe₂O₃, which means it contains two iron atoms and three oxygen atoms. We calculate the molar mass as follows:
Iron:
[tex]2 \times 55.8 \text{ g/mol} = 111.6 \text{ g/mol}[/tex]Oxygen:
[tex]3 \times 16.0 \text{ g/mol} = 48.0 \text{ g/mol}[/tex]Total Molar Mass of Fe₂O₃:
[tex]111.6 \text{ g/mol} + 48.0 \text{ g/mol} = 159.6 \text{ g/mol}[/tex]
Now that we know the molar mass of Fe₂O₃ is 159.6 g/mol, we can calculate the mass of 0.500 moles of Fe₂O₃ using the formula:
[tex]\text{mass} = \text{moles} \times \text{molar mass}[/tex]
Substitute the values:
[tex]\text{mass} = 0.500 \text{ moles} \times 159.6 \text{ g/mol}[/tex]
[tex]\text{mass} = 79.8 \text{ g}[/tex]
Therefore, there are approximately 79.8 grams of iron(III) oxide in 0.500 moles of the substance.
The correct option from the multiple-choice answers is closest to 79.9 g, so the answer is 79.9 g.
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