Thank you for visiting A rifle is aimed horizontally at a target 86 48 m away The bullet hits the target 2 58 cm below the aim point What. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
After applying the kinematic relation, the bullet’s flight time would be 0.0726 s
The kinematic equations are a set of four equations that can be used to make predictions about information regarding an item's motion that is unknown, provided that other information regarding the motion of the object is known. The equations can be applied to any motion that can be characterized as either having a constant velocity (an acceleration of 0 m/s/s) or a constant acceleration (an acceleration of 0 m/s/s), and they can be used to analyze both types of motion. They are never permitted to be used during any time frame in which the acceleration is undergoing a change.
In this case we will be using the third kinematic relation:
d = vt + ½ gt²
in this case, we are given that:
d = (2.58 cm × ( 1 m ÷ 100 cm))
v = 0 m/s
g = 9.8 m/s
Thus, the bullet’s flight time would be:
(2.58 cm × ( 1 m ÷ 100 cm)) = (0 m/s) × t + ½ (9.8 m/s) × t²
½ (9.8 m/s) × t² = (2.58 cm × ( 1 m ÷ 100 cm))
T = √0.005265
T = 0.0726 s
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