High School

Thank you for visiting What is the total electric flux due to these two point charges through a spherical surface centered at the origin and with radius tex r. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!

What is the total electric flux due to these two point charges through a spherical surface centered at the origin and with radius [tex] r = 1.70 \, \text{m} [/tex]? Express your answer in newtons times meters squared per coulomb.

What is the total electric flux due to these two point charges through a spherical surface centered at the origin and with radius [tex] r = 2.60 \, \text{m} [/tex]? Express your answer in newtons times meters squared per coulomb.

Answer :

The electric flux (Φ) through a closed surface is given by the equation:

Φ = Q[tex]_{enclosed}[/tex]/ εâ‚€. The electric flux using Gauss's law: Φ = Q[tex]_{enclosed}[/tex] / εâ‚€. where εâ‚€ is the permittivity of free space (εâ‚€ = 8.854 × 10⁻¹² N·m²/C²).

To find the total electric flux due to the two point charges through a spherical surface centered at the origin, we can use Gauss's law, which states that the total electric flux through a closed surface is equal to the enclosed charge divided by the permittivity of free space (εâ‚€). The electric flux (Φ) through a closed surface is given by the equation:

Φ = Q[tex]_{enclosed}[/tex]/ εâ‚€

For the first case, where the spherical surface has a radius r₁ = 1.70 m, we need to calculate the enclosed charge. Since the charges are located at the origin, the enclosed charge is the sum of the magnitudes of the two charges.

Q[tex]_{enclosed}[/tex] = |q₁| + |q₂|

For the second case, where the spherical surface has a radius râ‚‚ = 2.60 m, we follow the same procedure to calculate the enclosed charge.

Q[tex]_{enclosed}[/tex] = |q₁| + |q₂|

Once we have the values of the enclosed charge, we can calculate the electric flux using Gauss's law:

Φ = Q[tex]_{enclosed}[/tex] / εâ‚€

where εâ‚€ is the permittivity of free space (εâ‚€ = 8.854 × 10⁻¹² N·m²/C²).

To know more about Gauss's law

https://brainly.com/question/14773637

#SPJ4

Thank you for reading the article What is the total electric flux due to these two point charges through a spherical surface centered at the origin and with radius tex r. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

Rewritten by : Jeany