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A recreational vessel is approaching a US Naval vessel. At what distance from the US Naval vessel must the recreational vessel slow to minimum speed?

Option 1: 500 yards
Option 2: 1000 yards
Option 3: 2000 yards
Option 4: 3000 yards

Answer :

Final answer:

To approach the second ship at a speed of 0.999c as seen by the second ship, the canister shot from the first ship must be launched at a speed of 0.897c.

Explanation:

In order to approach the second ship at a speed of 0.999c, as seen by the second ship, the canister shot from the first ship must be launched at a speed of 0.897c.

Explanation:

To solve this, we need to use the relativistic velocity addition formula: v' = (v + u)/(1 + (vu)/c^2), where v' is the velocity as seen by the second ship, v is the velocity of the second ship, u is the velocity of the canister relative to the first ship, and c is the speed of light.

Substituting the given values into the formula, we have:

v' = (0.999c + (-0.800c))/(1 + ((0.999c)(-0.800c))/(c^2))

Simplifying this equation gives us:

v' = 0.199c/0.3604

v' ≈ 0.552c

Therefore, the canister must be shot from the first ship at a speed of 0.897c in order to approach the second ship at a speed of 0.999c as seen by the second ship.

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Rewritten by : Jeany

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