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Answer :
To determine the pOH of a solution when you know the concentration of hydroxide ions [tex]\([\text{OH}^-]\)[/tex], you can use the formula:
[tex]\[ \text{pOH} = -\log_{10}[\text{OH}^-] \][/tex]
Here's a step-by-step breakdown of how to solve this:
1. Identify the concentration of hydroxide ions:
- The concentration given is [tex]\([\text{OH}^-] = 2.0 \times 10^{-2}\)[/tex].
2. Apply the formula for pOH:
- Substitute the hydroxide ion concentration into the formula:
[tex]\[ \text{pOH} = -\log_{10}(2.0 \times 10^{-2}) \][/tex]
3. Calculate the logarithm:
- Use a calculator to find [tex]\(-\log_{10}(2.0 \times 10^{-2})\)[/tex].
- This gives approximately 1.69897.
Therefore, the pOH of the solution is approximately 1.70.
Given the answer choices, the correct answer is:
C. 1.70
[tex]\[ \text{pOH} = -\log_{10}[\text{OH}^-] \][/tex]
Here's a step-by-step breakdown of how to solve this:
1. Identify the concentration of hydroxide ions:
- The concentration given is [tex]\([\text{OH}^-] = 2.0 \times 10^{-2}\)[/tex].
2. Apply the formula for pOH:
- Substitute the hydroxide ion concentration into the formula:
[tex]\[ \text{pOH} = -\log_{10}(2.0 \times 10^{-2}) \][/tex]
3. Calculate the logarithm:
- Use a calculator to find [tex]\(-\log_{10}(2.0 \times 10^{-2})\)[/tex].
- This gives approximately 1.69897.
Therefore, the pOH of the solution is approximately 1.70.
Given the answer choices, the correct answer is:
C. 1.70
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