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A rifle is used to shoot twice at a target, using identical cartridges. The first time, the rifle is aimed parallel to the ground and directly at the center of the bull's-eye. The bullet strikes the target at a distance of \( h_a \) below the center. The second time, the rifle is similarly aimed, but from twice the distance from the target. This time, the bullet strikes the target at a distance of \( h_p \) below the center. Find the ratio \( \frac{h_p}{h_a} \).

Answer :

given data

a rifle is used to shoot twice at a target, using identical car- the first time, the rifle is aimed parallel to the ground and directly at the center of the bull's-eye. the bullet strikes the target at a distance of ha below the center, however. the second time, the rifle is similarly aimed, but from twice the distance from the target. this time the bullet strikes the target at a distance of hp below the center.

x a = U a ta…….(1)

;ha=1/2×gta2

;x p=up tp…….(2)

;hp=1/2×gtp2

Dividing equation 1 and 2

;1/2= u a ta /up tp

;hp/ha=tp2/ta2

;tp/ta=2

Put the value of hp/ha

;hp/ha=2×2

;hp/ha=4

the ratio of hp/ha is 4

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