Thank you for visiting A door is 0 822 m wide and has a mass of 35 9 kg What is its moment of inertia. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
The moment of inertia for a door with a width of 0.822 m and a mass of 35.9 kg, assuming it is thin and rotates about an axis at one edge (y-axis), is approximately 8.113 kgm^2.
Explanation:
To calculate the moment of inertia for a door, we can use the formula for a rectangular object rotating around an edge perpendicular to the width. In this case, let us consider the width of the door, 0.822 m, to be distance a from the axis of rotation, and the mass of the door to be 35.9 kg. The moment of inertia I for a rectangular object is given by I = 1/3 * mass * (width)^2. Therefore, plugging in the values, we get:
I = 1/3 * 35.9 kg * (0.822 m)^2
This calculation yields
I = 1/3 * 35.9 kg * 0.676 m^2
= 8.113 kgm^2 approximately.
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