Thank you for visiting A 2 75 molar aqueous solution of glucose has a density of 1 17 g mL What is the mass percentage m m of glucose. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Answer: The mass percentage of glucose in the solution is 42.38%.
Explanation:
To find the mass percentage of glucose in the solution, we need to calculate the mass of glucose in the given volume of the solution and then express it as a percentage.
First, let's calculate the mass of the solution. The density of the solution is given as 1.17 g/mL, and we know the volume of the solution is not provided. Therefore, we cannot determine the exact mass of the solution.
However, we can still proceed by assuming that we have 100 mL of the solution. So, the mass of the solution would be 100 mL * 1.17 g/mL = 117 g.
Next, let's calculate the moles of glucose in the solution. The molarity of the solution is given as 2.75 mol/L, and we know that the molar mass of glucose is 180.156 g/mol. Therefore, the moles of glucose in 100 mL of the solution would be 2.75 mol/L * (100 mL/1000 mL) = 0.275 mol.
Finally, we can calculate the mass of glucose in 100 mL of the solution using its molar mass: 0.275 mol * 180.156 g/mol = 49.56 g.
Now, to find the mass percentage of glucose, we divide the mass of glucose by the mass of the solution and multiply by 100: (49.56 g / 117 g) * 100 = 42.38%.
Therefore, the mass percentage of glucose in the solution is 42.38%.
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Rewritten by : Jeany
The mass percentage of glucose in the solution is 42.38%.
To find the mass percentage of glucose in the solution, we need to calculate the mass of glucose in the given volume of the solution and then express it as a percentage.
First, let's calculate the mass of the solution. The density of the solution is given as 1.17 g/mL, and we know the volume of the solution is not provided. Therefore, we cannot determine the exact mass of the solution.
However, we can still proceed by assuming that we have 100 mL of the solution. So, the mass of the solution would be 100 mL * 1.17 g/mL = 117 g.
Next, let's calculate the moles of glucose in the solution. The molarity of the solution is given as 2.75 mol/L, and we know that the molar mass of glucose is 180.156 g/mol. Therefore, the moles of glucose in 100 mL of the solution would be 2.75 mol/L * (100 mL/1000 mL) = 0.275 mol.
Finally, we can calculate the mass of glucose in 100 mL of the solution using its molar mass: 0.275 mol * 180.156 g/mol = 49.56 g.
Now, to find the mass percentage of glucose, we divide the mass of glucose by the mass of the solution and multiply by 100: (49.56 g / 117 g) * 100 = 42.38%.
Therefore, the mass percentage of glucose in the solution is 42.38%.
Learn more about mass percentage from the given link
https://brainly.com/question/27574467
#SPJ11
