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Answer :
Final answer:
The amount of snow accumulated on a 20.0 feet by 20.0 feet lawn with a snowfall rate of 1250 snowflakes per square foot per minute and an average snowflake mass of 1.70 mg is 51 kg after one hour.
Explanation:
If your front lawn is 20.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1250 new snowflakes every minute, how much snow, in kilograms, accumulates on your lawn per hour? Assume an average snowflake has a mass of 1.70 mg.
First, let's calculate the total number of snowflakes that accumulate on the lawn per hour:
- Lawn area = 20.0 feet * 20.0 feet = 400 square feet.
- Snowflakes per square foot per minute = 1250.
- Minutes in an hour = 60.
- Total snowflakes per hour = 400 * 1250 * 60 = 30,000,000 snowflakes.
Next, convert the total mass of snowflakes from milligrams to kilograms:
- Average mass of one snowflake = 1.70 mg.
- Total mass of snowflakes = 30,000,000 snowflakes * 1.70 mg/snowflake = 51,000,000 mg.
- Convert to kilograms (1000 mg = 1 g and 1000 g = 1 kg): 51,000,000 mg = 51,000 g = 51 kg.
Therefore, the amount of snow that accumulates on your lawn per hour, in kilograms, is 51 kg.
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