Thank you for visiting Two charges 9 68 microcoulombs and 1 70 microcoulombs are placed on a straight line 8 25 meters apart Calculate the magnitude of the electric. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
The magnitude of the electric field halfway between the two charges is approximately 1.31 x 10^5 N/C.
Explanation:
To calculate the magnitude of the electric field halfway between the two charges, we can use the formula:
E = k × |q1 - q2| / r
where:
- E is the magnitude of the electric field
- k is the electrostatic constant (9 × 10^9 N m^2/C^2)
- q1 and q2 are the charges
- r is the distance between the charges
In this case, q1 = 9.68 microcoulombs, q2 = 1.70 microcoulombs, and r = 8.25 meters. Plugging these values into the formula, we get:
E = (9 × 10^9 N m^2/C^2) × |9.68 × 10^-6 C - 1.70 × 10^-6 C| / (8.25 / 2)
Simplifying this expression, we find that the magnitude of the electric field halfway between the charges is approximately 1.31 × 10^5 N/C.
Thank you for reading the article Two charges 9 68 microcoulombs and 1 70 microcoulombs are placed on a straight line 8 25 meters apart Calculate the magnitude of the electric. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
- You are operating a recreational vessel less than 39 4 feet long on federally controlled waters Which of the following is a legal sound device
- Which step should a food worker complete to prevent cross contact when preparing and serving an allergen free meal A Clean and sanitize all surfaces
- For one month Siera calculated her hometown s average high temperature in degrees Fahrenheit She wants to convert that temperature from degrees Fahrenheit to degrees
Rewritten by : Jeany
