Answer :

Final answer:

By utilizing the properties of a rhombus and the SAS Postulate, we can formally prove that Triangle AEB is congruent to Triangle CEB. The equality of sides AE and CE, the shared side BE, and the right angles at E make the two triangles congruent.

Explanation:

The given problem involves a rhombus and the task is to prove that two triangles within the rhombus are congruent. To prove that Triangle AEB is congruent to Triangle CEB, we can use the following properties and theorems:

  1. In a rhombus, all sides are of equal length, so we have AB = BC = CD = DA.
  2. The diagonals of a rhombus bisect each other at right angles. So, diagonal BD bisects diagonal AC at E, and we have AE = CE and BE = DE. Also, angle AEB and angle CEB are right angles.
  3. By the definition of a rhombus, we can deduce that Triangle AEB and Triangle CEB are right triangles.
  4. SAS Postulate states that if two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle, the triangles are congruent.
  5. By applying the SAS Postulate to Triangle AEB and Triangle CEB, we note that AE = CE, BE is common, and angle AEB is congruent to angle CEB as they are both right angles.
  6. Hence, by SAS Postulate, Triangle AEB is congruent to Triangle CEB.

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Rewritten by : Jeany