Thank you for visiting A rifle is aimed horizontally at a target 52 m away The bullet hits the target 2 1 cm below the aim point What was. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
The time of the bullet's flight is approximately 0.066 seconds. Furthermore, the bullet's speed as it left the barrel was approximately 790 m/s.
Explanation:
The subject of this question is Physics, specifically projectile motion and the concepts associated with it. The rifle is aimed horizontally, so for the purposes of this calculation, we will consider only the vertical component of its motion. The bullet hits the target 2.1cm (or 0.021m) below the aim point which can be treated as a displacement due to gravity. We will use the equation of motion: h = 0.5gt².Where h is the height, g is the acceleration due to gravity (approx. 9.81ms⻲), and t is the time. Substituting the given values: 0.021 = 0.5*9.81*t² we can find t ≈ 0.066 seconds, This is the time of the bullet's flight. Iven that the horizontal distance traveled by the bullet was 52m and the time was 0.066 seconds, we can find the initial speed of the bullet (v) using the equation v = s/t Here, s is the distance and t is the time. Substituting the given values: v = 52/0.066 we can find that the bullet's speed as it left the barrel was approximately 787.87 m/s, which when rounded to a meaningful number of significant digits becomes ≈ 790 m/s.
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