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Star A has a magnitude of 6, and Star B has a magnitude of 15. How much brighter is Star A than Star B?

A. 1.5
B. 3815
C. 2.5
D. 2
E. 97.7
F. 0.0102
G. 6.25
H. 0.00164
I. 0.0002621
J. 5
K. 1526
L. 610
M. 0.0006554
N. 3.33
O. 0.16

Answer :

The correct answer is Option f. Star A is 512.45 times brighter than Star B, or in other words, Star A is 0.0102 times as bright as Star B.

The magnitude of a star refers to its brightness as seen from Earth.

The magnitude scale is such that a difference of 1 magnitude unit is equal to a brightness difference of 2.512.

If one star has a magnitude of 6, and the other has a magnitude of 15, the difference in magnitude between them is 9 (15 - 6 = 9).

The brightness difference can be calculated using the magnitude difference between the two stars, using the following formula: Brightness difference = [tex]2.512^{(magnitude difference)}[/tex]

In this case, the magnitude difference between the two stars is 9.

So, the brightness difference can be calculated as:

[tex]Brightness difference = 2.512^9 = 512.45[/tex]

Therefore, Star A is 512.45 times brighter than Star B, or in other words, Star A is 0.0102 times as bright as Star B.

Hence, the correct answer is f. 0.0102.

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