Thank you for visiting You have a sample of 39 4 g of CaCOâ ƒ How many moles of CaCOâ ƒ are in the sample. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
To calculate the number of moles of CaCO3 in a 39.4 g sample, you divide the sample's mass by the molar mass of CaCO3 (100.09 g/mol) to get approximately 0.394 moles.
Explanation:
To calculate the number of moles of CaCO3 in a 39.4 g sample, you need to use the molar mass of CaCO3. The molar mass of a compound is the sum of the masses of all the atoms in one mole of that compound.
The molar mass of calcium carbonate (CaCO3):
- Calcium (Ca) has an atomic mass of approximately 40.08 g/mol.
- Carbon (C) has an atomic mass of approximately 12.01 g/mol.
- Oxygen (O) has an atomic mass of approximately 16.00 g/mol, and there are three oxygen atoms.
So, the molar mass of CaCO3 is: 40.08 g (for Ca) + 12.01 g (for C) + 3 * 16.00 g (for O) = 100.09 g/mol.
Now, to find the moles of CaCO3 in the sample:
Moles of CaCO3 = mass of CaCO3 / molar mass of CaCO3 = 39.4 g / 100.09 g/mol ≈ 0.394 moles.
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