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Answer :
Certainly! Let's take a closer look at the function provided: [tex]\( f(t) = 3600(1.035)^t \)[/tex].
This function represents the amount of money in a savings account after [tex]\( t \)[/tex] years.
In this formula:
- The number [tex]\( 3600 \)[/tex] is a key part. This number is known as the "initial value" or "principal." It represents the amount of money in the savings account at the very beginning, before any interest is added. So, in this context, it is the initial amount of money deposited into the account.
- The expression [tex]\( (1.035)^t \)[/tex] represents the growth factor, which is applied to the initial amount each year to account for interest. The value 1.035 indicates a 3.5% annual increase (since 1 + 0.035 = 1.035) to the account's balance.
Given this understanding, the correct interpretation of the number 3600 in the context of the function [tex]\( f(t) \)[/tex] is:
The initial amount in the account is \[tex]$3600.
This means at \( t = 0 \) years, the account starts with \$[/tex]3600 before interest accumulates.
This function represents the amount of money in a savings account after [tex]\( t \)[/tex] years.
In this formula:
- The number [tex]\( 3600 \)[/tex] is a key part. This number is known as the "initial value" or "principal." It represents the amount of money in the savings account at the very beginning, before any interest is added. So, in this context, it is the initial amount of money deposited into the account.
- The expression [tex]\( (1.035)^t \)[/tex] represents the growth factor, which is applied to the initial amount each year to account for interest. The value 1.035 indicates a 3.5% annual increase (since 1 + 0.035 = 1.035) to the account's balance.
Given this understanding, the correct interpretation of the number 3600 in the context of the function [tex]\( f(t) \)[/tex] is:
The initial amount in the account is \[tex]$3600.
This means at \( t = 0 \) years, the account starts with \$[/tex]3600 before interest accumulates.
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