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Answer :
The volume of the helium gas at a pressure of 1.70 atm, and the temperature of 41 degrees celsius is 34.88 L
According to Ideal gas equation
P V = n R T
P = Pressure
V = Volume
n = Number of moles
R = Universal gas constant
T = Temperature
n = 2.3 moles
P = 1.7 atm
T = 41 °C
T = 41 + 273
T = 314 K
R = 0.0821 L atm / mol K
V = n R T / P
V = ( 2.3 * 0.0821 * 314 ) / 1.7
V = 59.29 / 1.7
V = 34.88 L
Therefore, the volume of the helium gas is 34.88 L
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