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Two similar separately-excited DC machines are connected through a shaft. One machine acts as a motor, connected to a 240 V supply, and the other acts as a generator, connected to a 99.8 Ω resistance. For each machine, the armature resistance [tex]r_a = 0.2 \, \Omega[/tex], and the brush voltage drop is negligible. Frictional losses are 140 W. If the motor is taking 40 A, what is the generator current?

Answer :

Final answer:

To find the generator current, use the formulas for back emf and Ohm's law. The generator current is approximately 2.326A.

Explanation:

To find the generator current, we first need to determine the back emf of the motor. The back emf can be calculated using the formula:

Eb = V - Ia * Ra

Where, Eb is the back emf, V is the supply voltage, Ia is the armature current, and Ra is the armature resistance. Plugging in the values, we get:

Eb = 240V - 40A * 0.2Ω

= 240V - 8V

= 232V

Now, we can find the generator current using Ohm's Law:

Ig = (Eb - V) / Rg

Where, Ig is the generator current and Rg is the resistance of the generator. Plugging in the values, we get:

Ig = (232V - 0V) / 99.8Ω

= 232V / 99.8Ω

= 2.326A

Therefore, the generator current is approximately 2.326A.

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