Thank you for visiting The mass of a particular eagle is twice that of a hunted pigeon Suppose the pigeon is flying north at tex v i 2 17. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Answer:
V=27.24 m/s
Explanation:
We need to apply the linear momentum conservation theorem:
[tex]m_1*v_{o1}+m_2*v_{o2}=m_t*v_{f}\\[/tex]
The velocity of the eagle its defined by its two components:
[tex]v_x=V*cos(\theta)\\v_y=V*sin(\theta)\\v_x=35.9*cos(61.9^o)=16.9m/s\\v_y=35.9*sin(61.9^o)=31.7m/s[/tex]
[tex]2*(16.9m/s(i)+31.66m/s(j))+17.9m/s(i)=3*v_f\\v_f=17.23m/s(i)+21.10m/s(j)[/tex]
because speed is a scalar value:
[tex]V=\sqrt{(21.10m/s)^2+(17.23)^2}\\V=27.24m/s[/tex]
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