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Answer :
The equations for the number of 197^ {Au} and 198^ {Au} nuclei as a function of time are derived. Conditions for secular equilibrium are discussed and it is determined that they are not met in this system. The activity of 198^ {Au} after 10 minutes of irradiation and the maximum value of N_{2} with this irradiation level are calculated.
The equations describing the number of 197^ {Au} and 198^ {Au} nuclei as a function of time are N_{1}(t) = N_{1}(0)e^{-σIt} and N_{2}(t) = N_{1}(0)(e^{-σIt} - e^{-λt}), where λ = 1/τ. To find N_{1}(0), we can use the given initial conditions: a pure gold foil initially contains only 197^ {Au}, so N_{1}(0) = 197^ {Au} atoms per unit surface area.
Secular equilibrium is a state where the rate of production of a radioactive isotope is equal to its decay rate. In this system, the production rate is σI and the decay rate is N_{2}/τ. If the production rate is greater than or equal to the decay rate, secular equilibrium is achieved. Here, the conditions for secular equilibrium are not met since σI < N_{2}/τ.
The activity of 198^ {Au} after 10 minutes of irradiation can be found using the equation A = λN_{2}, where λ is the decay constant. We can calculate N_{2} using the equation N_{2}(t) = N_{1}(0)(e^{-σIt} - e^{-λt}). Finally, to find the maximum value of N_{2}, we can differentiate N_{2}(t) with respect to t and set it to zero, then solve for t.
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