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Determine the specific heat of a material if a 35.9 g sample absorbed 96 J as it was heated from 293 K to 313 K.

Answer :

This is an incomplete question, here is a complete question.

Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.

Answer : The specific heat of a material is, 0.137 J/g.K

Explanation :

Formula used to calculate the specific heat of a material is:

[tex]q=m\times c\times (T_2-T_1)[/tex]

where,

q = heat absorbed = 96 J

m = mass of sample = 35 g

c = specific heat capacity of material = ?

[tex]T_1[/tex] = initial temperature = 293 K

[tex]T_2[/tex] = final temperature = 313 K

Now put all the given values in the above formula, we get:

[tex]96J=35g\times c\times (313-293)K[/tex]

[tex]c=0.137J/g.K[/tex]

Therefore, the specific heat of a material is, 0.137 J/g.K

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Rewritten by : Jeany

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