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Answer :
Final answer:
The amplification factor of a JFET with a transconductance of 3 A/V and a drain resistance of 100.2 Ω is calculated by multiplying the two values, resulting in an amplification factor of 300.6.
Explanation:
To calculate the amplification factor (also known as the voltage gain) of a Junction Field-Effect Transistor (JFET), we need to know the transconductance (gm) and the drain resistance (Rd). The amplification factor, often represented as Av, is given by the product of gm and Rd.
Given:
- Transconductance, gm = 3 A/V
- Drain resistance, Rd = 100.2 Ω
The amplification factor Av = gm * Rd.
So, Av = 3 A/V * 100.2 Ω = 300.6.
The JFET amplification factor for these given values would be 300.6, which means the signal's voltage will be amplified by this factor.
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