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A gas occupies a volume of 257 mL at a pressure of 99.8 kPa and a temperature of 295 K. When the pressure is changed, the volume becomes 116 mL. If there has been no change in the temperature and amount of gas, what is the new pressure in kPa?

Answer :

The new pressure is approximately 221.2 kPa when the volume changes to 116 mL, and there is no change in temperature or amount of gas.

Using the combined gas law (PV = nRT), we can solve for the new pressure. Since the temperature and amount of gas have not changed, we can simplify the equation to P1V1 = P2V2.
P1 = 99.8 kPa
V1 = 257 mL
V2 = 116 mL
P2 = (P1 x V1)/V2
P2 = (99.8 kPa x 257 mL)/116 mL
P2 = 221.4 kPa
The new pressure is approximately 221.2 kPa when the volume changes to 116 mL, and there is no change in temperature or amount of gas.

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