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A rifle is aimed horizontally at a target 30 meters away. The bullet hits the target 1.9 centimeters below the aiming point.

What is the bullet’s time of flight?

Answer :

Final answer:

Using the principles of projectile motion and the formula for the distance traveled under constant acceleration due to gravity, we calculate the time of flight for the bullet to be approximately 0.0199 seconds.

Explanation:

To determine the bullet's time of flight when the rifle is aimed horizontally at a target 30 m away, and the bullet hits the target 1.9 cm below the aiming point, we can use the principles of projectile motion. The time of flight for horizontal projectiles depends solely on the vertical motion, as the horizontal velocity remains constant assuming no air resistance.

Since we know the distance the bullet fell (1.9 cm or 0.019 m), we can use the formula for the distance traveled under constant acceleration, which is gravity. This distance can be expressed as distance = 0.5 * g * t^2, where g is the acceleration due to gravity (9.81 m/s²), and t is the time in seconds. By rearranging the formula to solve for time, we get t = sqrt((2 * distance) / g).

Here, the calculation would be as follows:
t = sqrt((2 * 0.019 m) / 9.81 m/s²)
t ≈ sqrt(0.003871 / 9.81)
t ≈ sqrt(0.00039497)
t ≈ 0.0199 seconds

Therefore, the time of flight for the bullet would be approximately 0.0199 seconds.

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Rewritten by : Jeany