Thank you for visiting Calculate the specific heat J g∠C J g ∠C for a 25 5 g g sample of a metal that absorbs 663 J. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
The specific heat of the metal is approximately 0.45 J/g°C.
To calculate the specific heat of the metal, we can use the formula
Q = mcΔT,
where Q is the heat energy absorbed, m is the mass of the sample, c is the specific heat, and ΔT is the change in temperature.
Rearranging the formula, we get c = Q/(mΔT).
Plugging in the values from the question,
c = 663 J / (25.5 g * (98.4 °C - 36.6 °C)).
Calculating the expression gives us a specific heat of approximately 0.45 J/g°C.
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