Thank you for visiting An 11 000 watt radio station transmits at 880 kHz Calculate the energy of a single photon at the transmitted frequency J photon A 5. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
The energy of a single photon at the transmitted frequency of an 11,000-watt radio station at 880 kHz is 5.8 x 10-28 J/photon.
Explanation:
To calculate the energy of a single photon at the transmitted frequency, we can use the formula:
Energy of a photon = Planck's constant x frequency.
Given that the radio station transmits at a frequency of 880 kHz (880,000 Hz) and Planck's constant is approximately 6.63 x 10-34 J s, we can calculate the energy as follows:
- Convert the frequency to Hz: 880 kHz = 880,000 Hz
- Multiply the Planck's constant by the frequency: (6.63 x 10-34 J s) x (880,000 Hz) = 5.8 x 10-28 J/photon
Therefore, the energy of a single photon at the transmitted frequency is 5.8 x 10-28 J/photon.
Learn more about Energy of a single photon here:
https://brainly.com/question/27905829
#SPJ12
Thank you for reading the article An 11 000 watt radio station transmits at 880 kHz Calculate the energy of a single photon at the transmitted frequency J photon A 5. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
- You are operating a recreational vessel less than 39 4 feet long on federally controlled waters Which of the following is a legal sound device
- Which step should a food worker complete to prevent cross contact when preparing and serving an allergen free meal A Clean and sanitize all surfaces
- For one month Siera calculated her hometown s average high temperature in degrees Fahrenheit She wants to convert that temperature from degrees Fahrenheit to degrees
Rewritten by : Jeany
Final answer:
The energy of a single photon at the transmitted frequency of an 11,000-watt radio station that transmits at a frequency of 880 kHz can be calculated using the Planck–Einstein relation (E=h*f), where 'h' is Planck's constant and 'f' is the frequency. The answer is 5.8 x 10^-28 J/photon.
Explanation:
To solve this problem, we need to understand the relationship between the energy of a photon, frequency, and Planck's constant. According to the Planck–einstein relation, the energy of a photon (E) can be calculated using the formula E=h*f, where 'h' is Planck's constant and 'f' is the frequency. The value of Planck's constant (h) is approximately 6.626 x 10-34 m2kg/s.
In this question, the frequency (f) of the radio station is given as 880 kHz or 880 x 103 Hz (since 1 kHz = 103 Hz).
Now, we can substitute these values into the equation E=h*f:
E = (6.626 x 10-34) * (880 x 103)
Solving this, we get E = 5.8308 x 10-28 J/photon. So, the answer is 5.8 x 10-28 J/photon.
Learn more about Energy of a Photon here:
https://brainly.com/question/34240307
#SPJ12
