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Answer :
The correct statement is AEB~CED by AAS.
Two triangles are similar by AAS (angle-angle-side) as we have only two angles in these two triangles in common
It is given that E is the midpoint of AC and BD.
Since E is the midpoint of AC and BD, we can conclude that
AC = 2AE and BD = 2DE.
Hence, we have AEB and CED as similar triangles.
These two triangles are similar by AAS (angle-angle-side) as we have only two angles in these two triangles in common and the side between them is also proportional.
Thus, the correct answer is: AEB~CED by AAS.
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