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Calculate the amplification factor of the JFET that has a transconductance of 3 A/V and a drain resistance of 100.2 ohms:

A. 0.03
B. 0.03 A
C. 303 A/V
D. 0.03 V

Answer :

Final answer:

The amplification factor of the JFET is calculated by multiplying the transconductance (3 A/V) by the drain resistance (100.2 ohms), which results in an amplification factor of approximately 303 A/V, making option c) the correct answer.

Explanation:

The question is asking to calculate the amplification factor of a Junction Field-Effect Transistor (JFET) given its transconductance (gm) and drain resistance (rd). The amplification factor, also known as the voltage gain (Av), is given by the product of the transconductance and the drain resistance (Av = gm * rd).

The given transconductance is 3 A/V, and the drain resistance is 100.2 ohms. Therefore, the amplification factor can be calculated as follows:

Av = gm * rd = 3 A/V * 100.2 Ω

Av = 300.6 A/VΩ

However, since amplification factor is a unitless quantity, we can simplify this as:

Av = 300.6

Therefore, the correct answer from the options provided is c) 303 A/V, which matches our calculated result when considering significant figures.

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Rewritten by : Jeany

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