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Answer :
The given value of the number of the moles is,
[tex]n=2.9\text{ mol}[/tex]The value of the temperature is,
[tex]\begin{gathered} T=25^{\circ}C \\ T=25+273.15 \\ T=298.15\text{ K} \end{gathered}[/tex]The value of the pressure is,
[tex]\begin{gathered} P=1.7\text{ atm} \\ P=172253\text{ Pa} \end{gathered}[/tex]By using the ideal gas equation,
[tex]PV=\text{nRT}[/tex]where R is the gas constant.
The value of the gas constant is,
[tex]R=8.3145m^3PaK^{-1}mol^{-1}[/tex]Substituting all the known values,
[tex]\begin{gathered} 172253\times V=2.9\times8.3145\times298.15 \\ V=0.042m^3 \end{gathered}[/tex]Thus, the value of the volume occupied by the oxygen gas is 0.042 meter cube.
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