Thank you for visiting Consider a buffer made by adding 35 9 g of tex CH 3 2NH tex to 250 0 mL of 1 42 M tex CH. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
A buffer solution is used to resist changes in pH. The pH of the buffer after adding 0.300 mol of H+ can be calculated using the Henderson-Hasselbalch equation.
Explanation:
A buffer solution is a solution that resists changes in pH when small amounts of acid or base are added. In this case, the (CH3)2NHâ‚‚ and (CH3)NH are part of a buffer solution. The (CH3)2NHâ‚‚ acts as a weak base and (CH3)NH acts as its conjugate acid.
To calculate the pH of the buffer after adding 0.300 mol of H+, we need to consider the chemical reaction:
(CH3)2NH₂ + H+ ⇌ (CH3)NH₂ + H2O
Since we're adding 0.300 mol of H+, we expect the reaction to shift to the right, consuming some of the (CH3)2NHâ‚‚ and producing (CH3)NHâ‚‚. The remaining (CH3)2NHâ‚‚ and (CH3)NH will then generate a specific pH based on their concentrations.
To find the pH, concentration of (CH3)2NHâ‚‚, and concentration of (CH3)NH, we need to use the given mass (35.9 g) and volume (250.0 mL) of (CH3)2NHâ‚‚, as well as the molarity of (CH3)NH (1.42 M). From there, we can calculate the pH using the Henderson-Hasselbalch equation.
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