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Answer :
35.9g x 1 mol/ 2.016g x 22.4 L/ 1 mol= 398.89 L
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Answer: 402.08 L
Explanation: According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
[tex]\text{Number of moles}=\frac{35.9 g}{2g/mol}=17.95moles[/tex]
Now 1 mole of [tex]H_2[/tex] molecule occupy= 22.4 L at STP
17.95 moles of [tex]H_2[/tex] molecule contains = [tex]\frac{22.4}{1}\times 17.95=402.08 L[/tex] at STP
