Answer :

Final answer:

The mass in grams of 1.73 moles of Calcium Hydride (CaHâ‚‚) is approximately 72.5g. This is calculated by first determining the molar mass of CaHâ‚‚ (42.10 g/mol) and then multiplying this by the given number of moles.

Explanation:

The question is asking about the calculation of mass of 1.73 moles of Calcium Hydride (CaHâ‚‚). The first step in answering this question is to find the molar mass of Calcium Hydride. In the Periodic Table, the molar mass of Calcium (Ca) is approximately 40.08 g/mol and that of Hydrogen (H) is approximately 1.01 g/mol. Since there are two atoms of Hydrogen in Calcium Hydride, the total molar mass becomes that of Calcium plus 2 times that of Hydrogen. Therefore, the molar mass of CaHâ‚‚ is 40.08 g/mol (for Ca) + 2*1.01 g/mol (for H) which totals to 42.10 g/mol.

Next, we multiply the number of moles by the molar mass to find the mass: 1.73 moles * 42.10 g/mol = ~72.8 g. Therefore, the mass in grams of 1.73 mol of CaHâ‚‚ is approximately 72.8g, which is closest to the answer choice b. 72.5g.

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Thank you for reading the article What is the mass in grams of 1 73 moles of CaHâ A 42 3 g B 72 5 g C 39 4 g D. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!

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