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Answer :
A mixture of 24.59 g zinc and sodium was reacted with Hâ‚‚SOâ‚„ and then with BaClâ‚‚ to form BaSOâ‚„. The percentage of sodium by mass in the mixture was found to be 16.97%.
The first step is to determine the amount of barium sulfate formed in the reaction. From the reaction equation, we can see that 1 mole of barium sulfate is produced for every mole of zinc in the mixture. Therefore, the amount of barium sulfate formed is:
24.59 g Zn x (1 mol Zn / 65.38 g Zn) x (1 mol BaSOâ‚„ / 1 mol Zn) x (233.39 g BaSOâ‚„ / 1 mol BaSOâ‚„) = 8.80 g BaSOâ‚„
Next, we need to calculate the amount of sodium in the original mixture. We can do this by subtracting the mass of zinc from the total mass of the mixture:
Mixture mass - Zinc mass = Sodium mass
24.59 g - (24.59 g x %Zn) = Sodium mass
We don't know the percent zinc by mass, but we can find it using the mass of barium sulfate formed. The mass percent of sodium in the mixture is then:
%Na = (Sodium mass / Mixture mass) x 100
To find the percent zinc by mass, we can subtract the percent sodium by mass from 100:
%Zn = 100 - %Na
Finally, we can substitute the values we found into the equations and solve for %Na:
8.80 g BaSOâ‚„ x (1 mol BaSOâ‚„ / 233.39 g BaSOâ‚„) x (1 mol Naâ‚‚SOâ‚„ / 1 mol BaSOâ‚„) x (142.04 g Naâ‚‚SOâ‚„ / 1 mol Naâ‚‚SOâ‚„) = 4.04 g Naâ‚‚SOâ‚„
Mixture mass - Zinc mass = Sodium mass
24.59 g - (24.59 g x %Zn) = Sodium mass
%Na = (Sodium mass / Mixture mass) x 100
Substituting the values we found:
%Na = (4.04 g / 24.59 g) x 100 = 16.4%
Therefore, the percent sodium by mass in the original mixture is 16.4%.
To know more about the percentage of sodium refer here :
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