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The probability that A hits a target is [tex]\frac{1}{3}[/tex], and the probability that B hits it is [tex]\frac{2}{5}[/tex]. What is the probability that the target will be hit if both A and B shoot at it?

Answer :

Final answer:

To calculate the probability that the target will be hit by either A or B, subtract the probability that neither A nor B hit the target from 1. The result is a probability of 0.6, or 3/5, that the target will be hit.

Explanation:

The probability that both A and B hit the target can be found by subtracting the probability that neither hits from 1. The probability that A does not hit the target is 1 - (1/3), and the probability that B does not hit is 1 - (2/5). Thus, the probability that neither A nor B hit the target is (1 - (1/3)) × (1 - (2/5)).

To calculate: 1 - [(2/3) × (3/5)] = 1 - (6/15) = 1 - (2/5) = 3/5 or 0.6. Therefore, the probability that the target will be hit by either A or B is 0.6.

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