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Answer :
To find the molarity of a solution, you'll need to follow these steps:
1. Determine the number of moles of the solute (LiCl):
- First, you need to know the mass of lithium chloride (LiCl) dissolved in the solution, which is given as 39.4 grams.
- Next, you use the molar mass of LiCl to convert the mass into moles. The molar mass of LiCl is 42.39 grams per mole.
- Calculate the moles of LiCl using the formula:
[tex]\[
\text{moles of LiCl} = \frac{\text{mass of LiCl}}{\text{molar mass of LiCl}}
\][/tex]
- Plug in the values:
[tex]\[
\text{moles of LiCl} = \frac{39.4 \, \text{g}}{42.39 \, \text{g/mol}} \approx 0.929
\][/tex]
2. Calculate the molarity of the solution:
- Molarity (M) is defined as the number of moles of solute per liter of solution.
- You are given the volume of the solution as 1.59 liters.
- Use the formula for molarity:
[tex]\[
\text{Molarity (M)} = \frac{\text{moles of LiCl}}{\text{volume of solution in liters}}
\][/tex]
- Plug in the values:
[tex]\[
\text{Molarity (M)} = \frac{0.929 \, \text{moles}}{1.59 \, \text{L}} \approx 0.585 \, \text{M}
\][/tex]
So, the molarity of the solution is approximately 0.585 mol/L.
1. Determine the number of moles of the solute (LiCl):
- First, you need to know the mass of lithium chloride (LiCl) dissolved in the solution, which is given as 39.4 grams.
- Next, you use the molar mass of LiCl to convert the mass into moles. The molar mass of LiCl is 42.39 grams per mole.
- Calculate the moles of LiCl using the formula:
[tex]\[
\text{moles of LiCl} = \frac{\text{mass of LiCl}}{\text{molar mass of LiCl}}
\][/tex]
- Plug in the values:
[tex]\[
\text{moles of LiCl} = \frac{39.4 \, \text{g}}{42.39 \, \text{g/mol}} \approx 0.929
\][/tex]
2. Calculate the molarity of the solution:
- Molarity (M) is defined as the number of moles of solute per liter of solution.
- You are given the volume of the solution as 1.59 liters.
- Use the formula for molarity:
[tex]\[
\text{Molarity (M)} = \frac{\text{moles of LiCl}}{\text{volume of solution in liters}}
\][/tex]
- Plug in the values:
[tex]\[
\text{Molarity (M)} = \frac{0.929 \, \text{moles}}{1.59 \, \text{L}} \approx 0.585 \, \text{M}
\][/tex]
So, the molarity of the solution is approximately 0.585 mol/L.
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