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Enter your answer in the provided box. A volume of 38.2 mL of a 0.168 M Ca(NO3)2 solution is mixed with 90.5 mL of a 1.196 M Ca(NO3)2 solution. Calculate the concentration of the final solution. M M

Answer :

Final answer:

The concentration of the final solution is 0.890 M.

Explanation:

To calculate the concentration of the final solution, we can use the formula:

C1V1 + C2V2 = C3V3

Where:

  • C1 is the concentration of the first solution
  • V1 is the volume of the first solution
  • C2 is the concentration of the second solution
  • V2 is the volume of the second solution
  • C3 is the concentration of the final solution (which we need to find)
  • V3 is the volume of the final solution (which is the sum of the volumes of the two solutions)

Given:

  • C1 = 0.168 M
  • V1 = 38.2 mL = 0.0382 L
  • C2 = 1.196 M
  • V2 = 90.5 mL = 0.0905 L

Let's substitute these values into the formula:

(0.168 M)(0.0382 L) + (1.196 M)(0.0905 L) = C3(0.0382 L + 0.0905 L)

Simplifying the equation:

0.0064176 + 0.108274 = C3(0.1287)

0.1146916 = 0.1287C3

Dividing both sides by 0.1287:

C3 = 0.890 M

Therefore, the concentration of the final solution is 0.890 M.

Learn more about concentration of a solution here:

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Rewritten by : Jeany

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