Thank you for visiting A car moving with an initial velocity of 35 9 m s slows down at a constant rate of 1 4 m s² a What. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
Hence, the car covers a distance of 265.4 meters in 9 seconds.
Explanation:
A car moving with an initial velocity of 35.9 m/s slows down at a constant rate of -1.4 m/s². To find its velocity after 9 seconds of deceleration and the distance it covers in this time, we use the equations of motion.
Velocity after 9 seconds
The final velocity (v) can be calculated using the equation v = u + at, where u is the initial velocity, a is the acceleration, and t is the time. Plugging in the values: v = 35.9 m/s + (-1.4 m/s²)(9 s) = 35.9 m/s - 12.6 m/s = 23.3 m/s. Thus, the car's velocity after 9 seconds is 23.3 m/s.
Distance covered in this time
To find the distance (s), we use the equation s = ut + ½at². Therefore, s = (35.9 m/s)(9 s) + ½(-1.4 m/s²)(9 s)² = 322.1 m - 56.7 m = 265.4 m.
Hence, the car covers a distance of 265.4 meters in 9 seconds.
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Rewritten by : Jeany
