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Answer :
Final answer:
The greatest number that will divide 307 and 330 with remainders 3 and 7 respectively is 1.
Explanation:
To find the greatest number that will divide 307 and 330 with remainders 3 and 7 respectively, we need to find their greatest common divisor (GCD).
Using the Euclidean algorithm:
- Divide 330 by 307: 330 ÷ 307 = 1 remainder 23
- Divide 307 by 23: 307 ÷ 23 = 13 remainder 8
- Divide 23 by 8: 23 ÷ 8 = 2 remainder 7
- Divide 8 by 7: 8 ÷ 7 = 1 remainder 1
- Divide 7 by 1: 7 ÷ 1 = 7 remainder 0
The last non-zero remainder is 1, so the GCD of 307 and 330 is 1.
Learn more about finding the greatest common divisor (gcd) here:
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